find the Greatest number which divides 615 and 963 ,leaving Reminder 6 in each Case . Question find the Greatest number which divides 615 and 963 ,leaving Reminder 6 in each Case . in progress 0 Math Kinsley 1 month 2021-10-22T00:27:41+00:00 2021-10-22T00:27:41+00:00 2 Answers 0 views 0

## Answers ( )

Answer:In this question, since remainder is six, so we will subtract 6 from 615 and 963 i.e. 609 and 957. Then, we will find the H.C.F. of 609 and 957, that is going to be our answer.

957= 3×11×29

609= 3×3×29

So, H.C.F.= 3×29= 87

hope it will help you

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.

Consider HCF be x.

In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.

609 = 3 x 3 x 29

957= 3 x 11 x 29

⇒ x = 3 x 29 = 87

∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.